Codeforces Problems' Solution (122A - Lucky Division) in C

#include<stdio.h> int main () { int n; scanf("%d", &n); if(((n % 4) == 0) || ((n % 7) == 0) || ((n % 44) == 0) || ((n % 47) == 0) | ((n % 74) == 0) || ((n % 444) == 0) || ((n % 447) == 0) || ((n % 474) == 0) || ((n % 477) == 0)) { printf("YES\n"); } else { printf("NO\n"); } return 0; }